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math121b:04-08 [2020/04/08 15:59]
pzhou created
math121b:04-08 [2026/02/21 14:41] (current)
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 $$ u(\vec x) = \int f(\vec x') G(\vec x, \vec x') d \vec x' = \int f(\vec x') \frac{-(4\pi)^{-1} }{|\vec x - \vec x'}} d \vec x'.$$ $$ u(\vec x) = \int f(\vec x') G(\vec x, \vec x') d \vec x' = \int f(\vec x') \frac{-(4\pi)^{-1} }{|\vec x - \vec x'}} d \vec x'.$$
  
-==== In other coordinates ====+==== In spherical coordinates ====
 Suppose the source function $f(\vec x)$ is given as $f(r, \theta, \phi)$. We now write $G(\vec x, \vec x')$ using spherical coordinate. Assume $\vec x$ has spherical coordinate $R=|\vec x|$, $\theta=0$ ($\phi$ doesn't matter). And assume $|\vec x| \gg |\vec x'|$ when $f(\vec x')\neq 0$, ie., we are sufficiently far away from the source. Then, we have  Suppose the source function $f(\vec x)$ is given as $f(r, \theta, \phi)$. We now write $G(\vec x, \vec x')$ using spherical coordinate. Assume $\vec x$ has spherical coordinate $R=|\vec x|$, $\theta=0$ ($\phi$ doesn't matter). And assume $|\vec x| \gg |\vec x'|$ when $f(\vec x')\neq 0$, ie., we are sufficiently far away from the source. Then, we have 
 $$ \frac{1}{|\vec x - \vec x'|} = \frac{1}{\sqrt{ |\vec x|^2 + |\vec x'|^2 - 2\vec x \cdot \vec x' } } = \frac{1}{\sqrt{ R^2 + r^2 - 2R r \cos \theta } } = \sum_{l=0}^\infty \frac{r^l P_l(\cos \theta)}{R^{l+1}}.$$ $$ \frac{1}{|\vec x - \vec x'|} = \frac{1}{\sqrt{ |\vec x|^2 + |\vec x'|^2 - 2\vec x \cdot \vec x' } } = \frac{1}{\sqrt{ R^2 + r^2 - 2R r \cos \theta } } = \sum_{l=0}^\infty \frac{r^l P_l(\cos \theta)}{R^{l+1}}.$$
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math121b/04-08.1586361596.txt.gz · Last modified: 2026/02/21 14:44 (external edit)