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math121a-f23:september_20_wednesday [2023/09/21 19:17]
pzhou [Method 3: change of variable]
math121a-f23:september_20_wednesday [2026/02/21 14:41] (current)
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 $$ $$
  I = \oint_{|w|=1/10, CW} \frac{1}{(w^{-1}-1)(w^{-1}-2)} d (w^{-1}) = \oint_{|w|=1/10, CW} \frac{-1}{(1-w)(1-2w)} dw = \oint_{|w|=1/10} \frac{1}{(1-w)(1-2w)} dw $$  I = \oint_{|w|=1/10, CW} \frac{1}{(w^{-1}-1)(w^{-1}-2)} d (w^{-1}) = \oint_{|w|=1/10, CW} \frac{-1}{(1-w)(1-2w)} dw = \oint_{|w|=1/10} \frac{1}{(1-w)(1-2w)} dw $$
-where in the last step, I changed the orientation of the contour from $CCW$ to $CW$ and put a $(-1)$ factor to the integral. +where in the last step, I changed the orientation of the contour from $CW$ to $CCW$(CCW is by default, hence omited) and add an extra $(-1)$ factor to the integral.  
 Since the integrand is only singular at $w=1,1/2$, and the contour $|w|=1/10$ contains no singularity in its interior, the integral is 0.  Since the integrand is only singular at $w=1,1/2$, and the contour $|w|=1/10$ contains no singularity in its interior, the integral is 0. 
 +
 +===== Riemann sphere =====
 +It is useful to think of add a point $\infty$ to the complex plane $\C$, and think of $\C \cup \{\infty\}$ as a sphere, where $\infty$ is identified with the north pole, $0$ with the south pole, the unit circle $|z|=1$ as the equator. 
 +
 +The natural coordinate to use near the north pole is $w=1/z$, so that $z=\infty$ corresponds to $w=0$.
 +
 +
 +
 +===== Exercises =====
 +Let $C$ be the contour of $|z|=10$. Consider the following integrals.
 +
 +(1) $$\oint_C \frac{1}{1+z^2} dz $$
 +
 +(2) (the result for this one is not zero.) 
 +$$\oint_C \frac{z}{1+z^2} dz $$
 +
 +(3) $$\oint_C \frac{z^2}{1+z^4} dz $$
 +
 +Apply methods 1,2,3 to the above problems (each method need to be used once)
 +
 +
  
  
  
  
math121a-f23/september_20_wednesday.1695323864.txt.gz · Last modified: 2026/02/21 14:44 (external edit)