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math121a-f23:september_11_monday [2023/09/13 05:59]
pzhou
math121a-f23:september_11_monday [2026/02/21 14:41] (current)
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 1. Taylor expand $(z+1)(z+2)$ around $z=3$. 1. Taylor expand $(z+1)(z+2)$ around $z=3$.
  
-2. Laurent expand $1/[(z+1)(z+2)]$ around $z=1$. And do it again, this time around $z=2$. +2. Laurent expand $1/[(z-1)(z-2)]$ around $z=1$. And do it again, this time around $z=2$. 
  
 2.5 (Optional) Laurent expand $e^{1/z + z}$ around $z=0$.  2.5 (Optional) Laurent expand $e^{1/z + z}$ around $z=0$. 
  
-3. You may have heard about Cauchy Riemann equation: it says the following: if $f(z)$ is a $\C$-valued function on $\C$, and let  $z = x+iy$, $f = u+iv$, then we can view $u,v$ as real valued functions depending on $x,y$. If $f$ is holomorphic, then we have+3. You may have heard about Cauchy Riemann equation: let $f(z)$ be a $\C$-valued function on $\C$, and let  $z = x+iy$, $f = u+iv$, then we can view $u,v$ as real valued functions depending on $x,y$.  
 + 
 +If $f$ is holomorphic, then we have
 $$ \frac{\d u(x,y)}{\d x} = \frac{\d v(x,y)}{\d y}, \quad \frac{\d v(x,y)}{\d x} = - \frac{\d u(x,y)}{\d y}$$ $$ \frac{\d u(x,y)}{\d x} = \frac{\d v(x,y)}{\d y}, \quad \frac{\d v(x,y)}{\d x} = - \frac{\d u(x,y)}{\d y}$$
-Either prove this, or verify that this is true for your favorite holomorphic function (don't choose $f$ to be a constant, too boring)+ 
 +Your task: either prove this in general if you feel strong, or verify that this is true for your favorite holomorphic function (don't choose $f$ to be a constant, too boring)
  
  
math121a-f23/september_11_monday.1694584770.txt.gz · Last modified: 2026/02/21 14:44 (external edit)