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| ====== October 6 (Friday) ====== | ====== October 6 (Friday) ====== | ||
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| + | Topics: | ||
| + | * Fourier inversion formula | ||
| + | * Fourier Series for periodic function | ||
| + | * Interpretation of complex vector space, hermitian inner product, orthonormal basis. | ||
| + | |||
| + | ===== Inversion Formula ===== | ||
| + | Suppose you started from $f(x)$, and did some hard work to get the Fourier transformation $F(p)$. Can you recover $f(x)$ from $F(p)$? Did you lose information when you throw away $f(x)$ and only keep $F(p)$? | ||
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| + | If $f(x)$ is continuous and absolutely integrable, we can recover $f(x)$ from $F(p)$ by | ||
| + | $$ f(x) = \frac{1}{2\pi} \int_{p \in \R} F(p) e^{ipx} dp $$ | ||
| + | The proof of this theorem is beyond the scope of this class. You might be happy to just accept the formal ' | ||
| + | $$ \frac{1}{2\pi} \int_\R e^{ipx - ipy} dp = \delta(x-y). $$ | ||
| + | and that | ||
| + | $$ f(x) = \int \delta(x-y) f(y) dy $$ | ||
| + | |||
| + | We can try some example to see if it works. | ||
| + | |||
| + | ===== Fourer Series ===== | ||
| + | If the function $f(x)$ is a periodic function, of period $L$, meaning $f(x) = f(x+L)$, then we cannot do Fourier transform (why?), but instead, we need to do Fourier series. | ||
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| + | We are not going to use all $e^{ipx}$ for all $p$, but only those that satisfies $e^{ipx} = e^{ip(x+L)}$ have the same periodicity. Which mean $p$ needs to satisfy | ||
| + | $$ p = (2\pi / L) n$$ for some integer $n$. | ||
| + | |||
| + | So, we define | ||
| + | $$ e_n(x) = e^{i(2\pi/ | ||
| + | We define the Fourer series coefficient as | ||
| + | $$ c_n = \frac{1}{L} \int_{0}^L f(x) \overline{e_n(x)} dx $$ | ||
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| + | Given these coefficient $c_n$, can we recover $f(x)$? Yes, under some smoothness condition of $f(x)$, we have | ||
| + | $$ f(x) = \sum_{n \in \Z} c_n e_n(x). $$ | ||
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