User Tools

Site Tools


math105-s22:notes:lecture_12

Differences

This shows you the differences between two versions of the page.

Link to this comparison view

Both sides previous revision Previous revision
Next revision
Previous revision
math105-s22:notes:lecture_12 [2022/02/24 07:58]
pzhou [Pugh 6.8: Vitali Covering]
math105-s22:notes:lecture_12 [2026/02/21 14:41] (current)
Line 32: Line 32:
 $$ \int F_+(x) dx = \int F_- (x) dx $$ $$ \int F_+(x) dx = \int F_- (x) dx $$
 hence $F_+(x) = F_-(x)$ for almost all $x$. Thus, for a.e. $x$, we have $\uint f(x,y) dy = \lint f(x,y) dy$, thus $\int f(x,y) dy$ exists for a.e. x.  hence $F_+(x) = F_-(x)$ for almost all $x$. Thus, for a.e. $x$, we have $\uint f(x,y) dy = \lint f(x,y) dy$, thus $\int f(x,y) dy$ exists for a.e. x. 
 +
 +==== A Lemma ====
 +Suppose $A$ is measurable, and $B \In A$ any subset, with $B^c = A \RM B$. Then
 +$$ m(A) = m^*(B) + m_*(B^c) $$
 +Proof: 
 +$$ m^*(B) = \inf \{ m(C) \mid A \supset C \supset B, C \text{measurable} \} = \inf \{ m(A) - m(C^c) \mid A \supset C \supset B, C \text{measurable} \} $$
 +$$ = m(A) - \sup \{ m(C^c) \mid A \supset C \supset B, C \text{measurable} \} = m(A) - \sup \{ m(C^c) \mid C^c \subset B^c, C^c \text{measurable} \} = m(A) - m_*(B^c) $$
  
 ===== Pugh 6.8: Vitali Covering ===== ===== Pugh 6.8: Vitali Covering =====
math105-s22/notes/lecture_12.1645689500.txt.gz · Last modified: 2026/02/21 14:43 (external edit)