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math104-s21:s:victoriatuck [2021/05/11 23:27]
73.158.208.111 [Questions]
math104-s21:s:victoriatuck [2026/02/21 14:41] (current)
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 a) Question: What is a counterexample to "If $A$ is closed, then $f(A)$ is closed". a) Question: What is a counterexample to "If $A$ is closed, then $f(A)$ is closed".
  
-Answer: Let $f := arctan(x)$. Then$(-\infty, \infty) -> (-\frac{\pi}{2}, \frac{\pi}{2})$.+Answer: Let $f := arctan(x)$. Then $(-\infty, \infty) -> (-\frac{\pi}{2}, \frac{\pi}{2})$.
  
 b) Question: What is a counterexample to "If $B$ is connected, then $f^{-1}(B)$ is connected."? b) Question: What is a counterexample to "If $B$ is connected, then $f^{-1}(B)$ is connected."?
  
-Answer:+Answer: Let $f := x^2$. Then $[1, \infty) -> (-\infty, -1] \cup [1, \infty)$, which is disconnected.
  
 6. Question: Given an open cover $\mathcal{U}$ of $f(E)$ where f is a continuous function and E is a compact set, why is $\{f^{-1}(U) : U \in \mathcal{U}\}$ a cover of E? [Question from Ross Theorem 21.4] 6. Question: Given an open cover $\mathcal{U}$ of $f(E)$ where f is a continuous function and E is a compact set, why is $\{f^{-1}(U) : U \in \mathcal{U}\}$ a cover of E? [Question from Ross Theorem 21.4]
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 Answer: In Ross 168, we define the inverse $f^{-1}(U)$ to include any value $s$ st $f(s) \in U$. So $f^{-1}([1, inf)) = (-inf, -1] \cup [1, inf)$. Answer: In Ross 168, we define the inverse $f^{-1}(U)$ to include any value $s$ st $f(s) \in U$. So $f^{-1}([1, inf)) = (-inf, -1] \cup [1, inf)$.
 +
 +8. Question: 
math104-s21/s/victoriatuck.1620775625.txt.gz · Last modified: 2026/02/21 14:44 (external edit)