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--- math104-s21:s:victoriatuck [2021/05/11 22:06]
73.158.208.111 [Questions]
+++ math104-s21:s:victoriatuck [2026/02/21 14:41] (current)
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 a) Question: What is a counterexample to "If $A$ is closed, then $f(A)$ is closed".
-Answer:
+Answer: Let $f := arctan(x)$. Then $(-\infty, \infty) -> (-\frac{\pi}{2}, \frac{\pi}{2})$.
 b) Question: What is a counterexample to "If $B$ is connected, then $f^{-1}(B)$ is connected."?
-Answer:
+Answer: Let $f := x^2$. Then $[1, \infty) -> (-\infty, -1] \cup [1, \infty)$, which is disconnected.
+. Question: Given an open cover $\mathcal{U}$ of $f(E)$ where f is a continuous function and E is a compact set, why is $\{f^{-1}(U) : U \in \mathcal{U}\}$ a cover of E? [Question from Ross Theorem 21.4]
+Answer: https://math.stackexchange.com/questions/605195/detail-on-a-theorem-of-continuity-and-compactness
+. Question: For non 1-to-1 functions (like $f = x^2$), how do we define the inverse $f^{-1}$ of a set in the range of that function? E.g., for $x^2$, what would $f^{-1}([1, inf))$ be?
+Answer: In Ross 168, we define the inverse $f^{-1}(U)$ to include any value $s$ st $f(s) \in U$. So $f^{-1}([1, inf)) = (-inf, -1] \cup [1, inf)$.
+. Question:

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